Mathematical Justification For A Flying Saucer - Alternative View

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Mathematical Justification For A Flying Saucer - Alternative View
Mathematical Justification For A Flying Saucer - Alternative View

Video: Mathematical Justification For A Flying Saucer - Alternative View

Video: Mathematical Justification For A Flying Saucer - Alternative View
Video: The Real Flying Saucer 2024, November
Anonim

… I'm not Tsiolkovsky, but the same from Kaluga.

/ Volodikov Andrey Vasilievich 25 sept. B. 1972 /

Everything is fantastic: … anti-gravity … anti-gravity … And here I counted …

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So … I will prove to you here that a spacecraft (a piece of iron) can "hover" (or rise with acceleration upward) over an asteroid or planet like a flying saucer without energy consumption.

Let's start with the essence of the problem of "zero gravity" HOW TO DISCELER THE APPARATUS TO THE FIRST SPACE WITHOUT TOUCHING IT FROM THE PLACE The answer is this - IT CAN BE DONE WITH A TORO (donut) IF IT IS UNLINKED AS YULU (or with 2 pieces of iron connected with a cable, then the cable length is 2ra). In this case, we are interested in the physics and mathematics of this process.

Physics is that we will defeat acceleration (free fall) by another acceleration - centrifugal. (fight fire with fire). And now we'll see how to do it.

Have you noticed the drawing? At the top there is a wonderful angle A, which is the greater the smaller the distance from the center of gravity of the asteroid to any point of the toroid, and also this angle the larger the larger the radius of the toroid, it follows that the ideal condition for our example will be when

Promotional video:

a toroid with a huge radius (for example, take = 10 meters) "hovers" over small Phobos (let's round the radius of Phobos to = 15000 meters)

Angle A is the angle between two VERTICALS, one of which passes through the center of the toroid (its hole) and the center of gravity of the asteroid (point O), and the second through the center of the torus side section (point A) and the center of gravity of the asteroid. So, we have the angle now let's see where the lifting acceleration -g comes from. To accelerate -g, we need another acceleration an - centrifugal, which is applied to point A (more precisely to all points of the torus) and is directed in the plane of the torus, which means that the acceleration vector is directed not strictly horizontally (at point A, the horizontal lines are indicated by red lines and are perpendicular to one of the verticals that passes through point A), but at some angle upward … It turns out something similar to the curvature of space near the torus (all accelerations

and are directed at an angle A vvehx if we take into account that the horizontal is not a plane but a sphere (asteroid) - here we have a lifting force !!! What is this -g? As you can see from the figure, -g depends on the value of an and the angle A, and then trigonomy went to find -g … sin-mustache cos-inus … such a ***** … which I will write about sometime later.

On this, let them take their leave.

(… I explain it on my fingers … tfu you on the vectors (for those who did not understand) the vector g (free fall acceleration) is added with an and we get the sum of vectors - if it is directed strictly parallel to the horizontal (for point A), then the toroid becomes weightless, and if it is lifts up a bit to the sky, then our "plate" rises into space with acceleration (even when the power supply is disconnected).

… from the formulas it turns out that the torus will rise (fix) to the orbital altitude which corresponds to its linear rotation speed = orbital speed for this altitude (the height R depends on the linear speed, and judging from the formulas, it corresponds (equal) to the orbital speed for this altitude)

The ego can be used as a geostationary object (on minor planets = Phobos type).

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… or another case.

If Saturn's rings were made iron, then the planet would look like this (Fig. On the left) the rings would hang near the poles of the planet - they would be held by the -g force

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The figure on the left shows that if the asteroid has 2 mascons (center of mass), then the torus will try to occupy a position on the axis passing through these points, in other words, the “plate” will be carried to the sharp ends of the asteroid (formula proofs are somewhere in the diaries - then I will post on this page).

… from old diaries

At the bottom of the formula from the diaries are those calculations, including the resistance of materials The main thing in the design of the plate is that the ratio of the density and the tensile strength of the material to rupture is sufficient so that the toroid breaks off the surface. planetoids) - and that's not bad, you can study, for example, Phobos and Deimos using tori instead of jet thrust, and for their promotion, electricity turns out to be a "perpetual motion machine" (I mean, no fuel is needed). I will write in more detail about the following formulas later (they contain the calculation of the strength requirement of the torus) Well, for example, the steel toroid has already collapsed, losing only 0.07266% in weight (for the Earth) and 1.612% for the Moon …

… count yourself R (earth) = 6375000 meters R (moon) = 1738000m

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where Fp is the force tending to break the toroid

m - mass

S cross-sectional area of the toroid side

H = R

angle j = angle A

the letter RO (a circle with a long tail to the left) is DENSITY

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It is also seen from the formulas that Fp (the force breaking the toroid) does not depend on the radius of the toroid.

AND EVERYTHING IS THAT THEY RETURN !!! And why did humanity not think of this earlier?